Question

The center of the circle below is at P. If the angle < APB measures 67°, and the radius is 13 cm., find the length of the arc AB in cm.. (round to the nearest tenth)

Answer 1

The length s of an arc enclosed by an angle θ (in degrees) in a circle with radius r is:

$s=\frac{\theta}{360º}\times2\pi r$

Replace θ=67º and r=13cm:

$s=\frac{67º}{360º}\times2\pi(13cm)=15.2018...cm\approx15.2cm$

Therefore, the correct choice is option C) 15.2cm.