Given:
The initial volume of the balloon, V₁=457 cm³=457×10⁻⁶ m³
The initial temperature of the balloon, T₁=270 K
The final temperature of the balloon, T₂=585 K
To find:
The new volume of the balloon.
Explanation:
From Charle's law,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]Where V₂ is the new volume of the balloon.
On substituting the known values,
[tex]\begin{gathered} \frac{457\times10^{-6}}{270}=\frac{V_2}{585} \\ \Rightarrow V_2=\frac{457\times10^{-6}}{270}\times585 \\ =990\times10^{-6}\text{ m}^3 \\ =990\text{ cm}^3 \end{gathered}[/tex]Final answer:
Thus the new volume of the balloon is 990 cm³
