ANSWER
[tex]CF_4+2Br_2\text{ }\rightarrow CBr_4+2F_2[/tex]
STEP-BY-BY STEP EXPLANATION:
Given equation
[tex]CF_4+Br_2\text{ }\rightarrow CBr_4+F_2[/tex]
To balance the above equation, we will need to apply the law of conservation of mass
The next process is to assign variables to each of the reactants and products
[tex]\text{aCF}_{4\text{ }}+bBr_2\text{ }\rightarrow cCBr_4+dF_2[/tex]
For carbon
we have 1 carbon atom at the reactant side and 1 carbon atom on the product side
Mathematically
a = c
For Fluorine
We have 4 atoms of fluorine at the reactant side and 2 atoms of fluorine at the product side
4a = 2d
For Bromine
we have 2 atoms of bromine on the reactant side and 4 bromine atoms on the product side.
2b = 4c
Since a = c
Therefore, a = 1 and c = 1
2b = 4c
Recall that, c = 1
2b = 4
Divide both sides by 2
2b/2 = 4/2
b = 2
we also know that, 4a = 2d
a = 1
4(1) = 2d
4 = 2d
Divide both sides by 2
4/2 = 2d/2
d = 2
Therefore,
a = 1
b = 2
c = 1
d = 2
