Answer:
102 feet
Explanation:
First, find the length of AB:
In the larger triangle ADC:
[tex]\begin{gathered} \sin 30=\frac{80}{AB+42} \\ 0.5=\frac{80}{AB+42} \\ 0.5(AB+42)=80 \\ AB+42=\frac{80}{0.5} \\ AB=160-42 \\ AB=118 \end{gathered}[/tex]Since we already know the length of AB:
[tex]\begin{gathered} \cos 30=\frac{AE}{AB} \\ \cos 30=\frac{AE}{118} \\ AE=118\times\cos 30 \\ AE=102.19 \\ AE\approx102\text{ f}eet \end{gathered}[/tex]The distance from Point A on one bank to Point E on the opposite bank is closest to 102 feet.