Which angle in the figure below measures 90 degrees? Explain how you know

Given that
[tex]\angle\text{BKD}=70^o\text{ and }\angle\text{DKC}=20^o[/tex]We know that
[tex]\angle BKC=\angle BKD+\angle DKC[/tex][tex]\text{ Substitute }\angle\text{BKD}=70^o\text{ and }\angle\text{DKC}=20^o,\text{ we get}[/tex][tex]\angle BKC=70^o+20^o[/tex]Adding 70 and 20, we get
[tex]\angle BKC=90^o[/tex]Hence the angle BKC is 90 degrees.