To solve an equation as given:
1. Remove the parenthesis by multiplying the terms in the parenthesis for the term outside the parenthesis:
[tex]\begin{gathered} 6\cdot5x-6\cdot2=48 \\ 30x-12=48 \end{gathered}[/tex]2. Add 12 in both sides of the equation:
[tex]\begin{gathered} 30x-12+12=48+12 \\ 30x=60 \end{gathered}[/tex]3. Divide both sides of the equation into 30:
[tex]\begin{gathered} \frac{30x}{30}=\frac{60}{30} \\ \\ x=2 \end{gathered}[/tex]Then, the solution ofr the given equation is x=2