Given:
For every corresponding pair of cross sections, the area of the cross-section of a sphere with radius r is equal to the area of the cross-section of a cylinder with radius r and height 2r minus the volume of two cones, each with a radius and height of .....
Required:
We need to find the height of the given cone.
Explanation:
Recall that Cavalieri's principle tells us that if 2 figures have the same height and the same cross-sectional area at every point along that height, they have the same volume.
The area of the cross-section of the sphere is an area of the circle with a radius r.
[tex]A=\pi r^2[/tex]
The area of the cross-section of the cylinder is again area of the circle with radius r.
We know that the volume of the two cones is equal.
So the radius and height of the cone is r.
Final answer: