Question

Use the discriminant to find the nature of the solutions to the following quadratic equation:-4x^2+40x-100=0 Two imaginary-number solutionsTwo different rational-number solutionsOne repeated irrational-number solutionsTwo different irrational-number solutionsOne repeated rational-number solutions

Answer 1

The given expression is

$-4x^2+40x-100=0$

The discriminant is

$b^2-4ac$

When a = -4, b = 40, and c = -100. Let's replace these values.

$(40)^2-4(-4)(-100)=1600-1600=0$

Since the discriminant is zero, we deduct that the equation has one unique solution.

Therefore, the answer is E.