Question

The perimeter of a rectangular garden is 286 feet the width of the garden is 66 feet what is the length?

Answer 1

To answer this question, we need to remember that the perimeter of a rectangle is given by:

$P_{\text{rectangle}}=2l+2w$

Where

• l is the length of the rectangle.

,

• w is the width of the rectangle.

If we have that:

• P = 286ft

,

• w = 66ft

Then we have (without units):

$P=2l+2w\Rightarrow286=2l+2(66)$

Therefore

$286=2l+132$

Now, to solve for l, we need to subtract 132 from both sides of the equation, and then divide both sides by 2:

$286-132=2l+132-132\Rightarrow154=2l\Rightarrow\frac{154}{2}=\frac{2l}{2}$

Finally, we have:

$l=\frac{154}{2}\Rightarrow l=77$

Therefore, the length of the rectangular garden is equal to 77 feet.