Question

Ok for a pattern in the table. Find the missing addends and sums. Addends: 1/8+1/4 1/4+1/4 3/8+1/4Sum: 3/8 1/2

Answer 1

We have the following pattern

$\frac{n}{8}+\frac{1}{4}$

in the first column, we have

$\frac{1}{8}+\frac{1}{4}=\frac{1}{8}+\frac{2}{8}=\frac{3}{8}$

in the second column we have:

$\frac{2}{8}+\frac{1}{4}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$

in the third one:

$\frac{3}{8}+\frac{1}{4}=\frac{3}{8}+\frac{2}{8}=\frac{5}{8}$

-> so in the 3rd column the sum is 5/8

Now, in the 4th column we have:

$\frac{4}{8}+\frac{1}{4}=\frac{1}{2}+\frac{1}{4}=\frac{2}{4}+\frac{1}{4}=\frac{3}{4}$

-> thus, the addends are 1/2 + 1/4 and the sum is 3/4