To determine the angle of elevation
[tex]\begin{gathered} \text{ Using SOHCAHTOA} \\ \text{ Tan}\theta\text{ = }\frac{opp}{adj} \\ Tan10^0\text{ = }\frac{x}{0.9\text{ miles}} \\ x\text{ = 0.9 Tan10}^0 \\ x\text{ = }0.9\text{ x 0.1763} \\ x\text{ = 0.1587miles} \end{gathered}[/tex]conversion from miles to feet =
[tex]\begin{gathered} \text{ 1 mile = }5280foot \\ \text{ 0.9 miles = 0.1587 x 5280 f}eet \\ \text{ = }837.91\text{feet} \end{gathered}[/tex]Hence the height of the building is 837.91 feet