Answer:
0.630 L of oxygen must be added at constant temperature and pressure
Explanation:
According to Avodagro's law, the volume and the number of moles are directly proportional at constant temperature and pressure. What this is saying is that at increased volume, it is expected that we have more number of moles
Mathematically, we can represent this as:
[tex]\frac{v_1}{n_1}\text{ = }\frac{v_2}{n_2}[/tex]
The values with subscript 1 represent the initials, while the values with subscript 2 represent the finals
We can have the formula rewritten in terms of the missing value as follows:
[tex]\begin{gathered} v_1\text{ = }4\text{ L} \\ v_2\text{ = ?} \\ n_1\text{ = }0.864\text{ mol} \\ n_2\text{ = 1 mol} \\ v_2\text{ = }\frac{v_1n_2}{n_1} \end{gathered}[/tex]
Using the formula, we have:
[tex]v_2=\text{ }\frac{4\times1}{0.864}\text{ = 4.63 L}[/tex]
What the question is asking is the extra volume to be added
That wold be calculated as follows:
[tex]\Delta v=v_2-v_1\text{ = 4.63 L - 4.0 L = 0.630 L}[/tex]
