Respuesta :

The tangen of an angle in a triangle is given by:

[tex]\tan \theta=\frac{\text{opp}}{\text{adj}}[/tex]

where opp and adj means the opposite and adjacent legs, respectively.

In this case we have that:

[tex]\tan G=\frac{EF}{FG}[/tex]

then we need to find the length of leg EF. Using the pythagorean theorem we have:

[tex]\begin{gathered} (\sqrt{24})^2=EF^2+3^2 \\ EF^2=(\sqrt{24})^2-3^2 \\ EF^2=15 \\ EF=\sqrt[]{15} \end{gathered}[/tex]

Now that we know the leg we need we have that:

[tex]\begin{gathered} \tan G=\frac{\sqrt[]{15}}{3} \\ \tan G=1.29 \end{gathered}[/tex]

Therefore the tangent of G is 1.29

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