Question

A holiday punch recipe calls for 1500 mL of fruit punch, 375 ml of pineapple juice, and 1 liter of ginger ale. How many liters (L) of punch will this recipe yield if doubled?a. 12.5Lb. 3.05Lc. 2.875 Ld. 5.75 L

Answer 1

Given:

1500mL of fruit punch

375mL of pineapple juice

1 L of ginger ale

Find: total amount of liters (L) if punch is doubled

Solution:

We need to convert each content of recipe first into liters. Remember that for 1 liter = 1000mL.

Let's start converting the fruit punch first.

$1500mL\times\frac{1L}{1000mL}=\frac{1500}{1000}=1.5L$

Now, let's convert the pineapple juice.

$375mL\times\frac{1L}{1000mL}=\frac{375}{1000}=0.375L$

So, we have:

1.5L of fruit punch

0.375L of pineapple juice

1 L of ginger ale

Let's add them all and then, double it.

$\begin{gathered} 1.5L+0.375L+1L=2.875L \\ \text{Double the recipe.} \\ 2\times2.875L=5.75L \end{gathered}$

Hence, there are 5.75L of punch of this recipe if doubled. (Option 4)