Question

Circle Parts QuizAn equation of the circle whose center is at (2, -3) and whose radius measures 4 is= 4O (x - 2)2 + (y + 3)?O (x + 2)2 + (y - 3)2 = 4O (x - 2)2 + (y + 3)2 = 16O (x + 2)2 + (y - 3)2= 16

Answer 1

Step 1: Write out the formula

$\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ \text{where} \\ (a,b)\text{ is the center of the circle} \\ r\text{ is the radius of the circle} \end{gathered}$

Step 2: Write out the given values and substitute them into the formula

In this case,

$a=2,b=-3,r=4$

Therefore, the equation is as follows

$\begin{gathered} (x-2)^2+(y-(-3))^2=4^2 \\ (x-2)^2+(y+3)^2=16 \end{gathered}$

Hence, the third option is the correct answer