Given data:
* The frequency of the revolution is f = 290 rev/min.
* The diameter of the wheels is d = 1.8 feet.
Solution:
The angular speed of the wheel is,
[tex]\begin{gathered} \omega=2\pi f \\ \omega=2\pi\times290 \\ \omega=1822\text{ radians/min} \end{gathered}[/tex]
Thus, the angular speed of the wheel is 1822 radians/minute.
(b). The radius of the wheels is,
[tex]\begin{gathered} r=\frac{d}{2} \\ r=\frac{1.8}{2} \\ r=0.9\text{ ft} \end{gathered}[/tex]
The linear speed of cyclist is,
[tex]\begin{gathered} v=r\omega \\ v=0.9\times1822 \\ v=1640\text{ ft/min} \end{gathered}[/tex]
Thus, the linear speed of the cyclist is 1640 feet/minute.
