Let 'x' and 'y' be the cost of one rose bush and one bunch of ornamental grass.
Given that Castel paid $69 for 5 rose bushes and 8 bunches of grass,
[tex]5x+8y=69\ldots(1)[/tex]
Also, given that Sumalee paid $42 for 2 rose bushed and 8 bunches of grass,
[tex]2x+8y=42\ldots(2)[/tex]
Now that we have two equations and two variables. These can be solved using the Elimination Method.
Subtract equation (2) from (1) as follows,
[tex]\begin{gathered} (5x+8y)-(2x+8y)=69-42 \\ 5x+8y-2x-8y=27 \\ 3x+0=27 \\ x=\frac{27}{3} \\ x=9 \end{gathered}[/tex]
Substitute this value in (1) and obtain the corresponding y-value,
[tex]\begin{gathered} 5(9)+8y=69 \\ 45+8y=69 \\ 8y=69-45 \\ y=\frac{69-45}{8} \\ y=3 \end{gathered}[/tex]
So the simultaneous solution is obtained as,
[tex]\begin{gathered} x=9 \\ y=3 \end{gathered}[/tex]
Thus, the cost of one rose bush is $9 and the cost of one bunch of ornamental grass is $3.