For this problem we have to calculate the probability that x is greater or larger than 28
[tex]\begin{gathered} P(x\ge28)=\Sigma P(x=i) \\ i\text{ goes from 28 to }40 \end{gathered}[/tex]For each i, the probability
[tex]P(x=i)=\frac{40!}{28!\cdot12!}\cdot0.8^i\cdot0.2^{40-i}[/tex]Now computing the sum:
[tex]P(x\ge28)=96[/tex]The answer is 96%