Find the length of the sides of the special triangles

We will have the following:
Firs, we can see that once we find one side we will have both, since they are equal.
Now, using the law of sines:
[tex]\frac{4}{\sin(90)}=\frac{Z}{\sin(45)}\Rightarrow Z=\frac{4\sin (45)}{\sin (90)}[/tex][tex]\Rightarrow Z=2\sqrt[]{2}[/tex]So, the length of side Z is 2sqrt(2).