Question

in triangle ABC, < A is the right angle, and m< B =45. find BC. if your answer is not the whole number, leave it in the simplest radical form

Answer 1

$\measuredangle B=45,\text{ }\measuredangle A=90,\text{ }\measuredangle C=45$$AC=11,\text{ BC=?}$$\sin (\measuredangle B)=\frac{AC}{BC}$$\sin (45)=\frac{11}{BC}$$\frac{\sqrt[]{2}}{2}=\frac{11}{BC}$$BC=\frac{11\cdot2}{\sqrt[]{2}}$$BC=11\sqrt[]{2}$