If a sample of gas occupies 23. 5 ml at 315 k and 14. 8 atm of pressure, what volume will it occupy at 415 k and 12. 3 atm?.

Respuesta :

The volume occupied by gas is 37.25 ml.

The ideal gas law will be used for calculation of volume. The mentioned ideal gas equation is as follows -

[tex] P_{1}[/tex] [tex] V_{1}[/tex]/ [tex] T_{1}[/tex] = [tex] P_{2}[/tex] [tex] V_{2}[/tex]/ [tex] T_{2}[/tex]. In the equation, values on LHS are initial pressure, volume and temperature. While the values in RHS are final pressure, volume and temperature.

Keep the values in mentioned formula to find the value of final volume.

[tex] V_{2}[/tex] = (14.8 × 23.5 × 415) ÷ (12.3 × 315)

Performing multiplication in both numerator and denominator on Right Hand Side of the equation

[tex] V_{2}[/tex] = 144,337 ÷ 3874.5

Performing division on Right Hand Side of the equation

[tex] V_{2}[/tex] = 37.25 ml

Thus, the final volume of given sample of gas is 37.25 ml.

Learn more about ideal gas equation -

https://brainly.com/question/20348074

#SPJ4

ACCESS MORE