Since we are dealing with a right triangle, we can use the following two trigonometric identities
[tex]\sin \theta=\frac{O}{H},\cos \theta=\frac{A}{H}[/tex]
Where theta is an inner angle of the right triangle, A and O are the adjacent and opposite sides to theta, and H is the hypotenuse.
In our case,
[tex]\sin (30dgr)=\frac{x}{22\sqrt[]{3}},\cos (30dgr)=\frac{y}{22\sqrt[]{3}}[/tex]
Thus,
[tex]\begin{gathered} \Rightarrow x=22\sqrt[]{3}\sin (30dgr),y=22\sqrt[]{3}\cos (30\text{dgr)} \\ \Rightarrow x=\frac{22\sqrt[]{3}}{2}=11\sqrt[]{3},y=22\sqrt[]{3}(\frac{\sqrt[]{3}}{2})=11\cdot3=33 \\ \Rightarrow x=11\sqrt[]{3},y=33 \end{gathered}[/tex]
Hence, the answers are x=11sqrt(3) and y=33
