Given:
The graph of the quadratic equation is given. The intersecting points on the graph are (-6,0) and (0,0).
Required:
To find the equation of the parabola.
Explanation:
The intercept points are given on the graph.
when x= -6 , y =0
Put x = -6 in the given option and find the value of y.
[tex]\begin{gathered} y=x^2+6x \\ y=(-6)^2+6(-6) \\ y=36-36 \\ y=0 \end{gathered}[/tex][tex]\begin{gathered} y=x^2-6x \\ y=(-6)^2-6(-6) \\ y=36+36 \\ y=72 \end{gathered}[/tex][tex]\begin{gathered} y=x^2+6x-12 \\ y=(-6)^2+6(-6)-12 \\ y=36-36-12 \\ y=-12 \end{gathered}[/tex][tex]\begin{gathered} y=x^2+6x+12 \\ y=(-6)^2+6(-6)+12 \\ y=36-36+12 \\ y=12 \end{gathered}[/tex]
Only option (1) gives the value of y=0.
Hence option (1) is the correct answer.
Final Answer:
Option first is the correct answer.
