Question Solve the following equation for B, where - a

We are to solve
[tex]5\tan ^2\beta+5\tan \beta=0[/tex]Dividing through by 5 we get
[tex]\tan ^2\beta+\tan \beta=0[/tex]Simplifying further we have
[tex]\tan \beta(1+\tan \beta)=0[/tex]This gives
[tex]\tan \beta=0,\tan \beta+1=0[/tex]For
[tex]\tan \beta=0[/tex]Since for every multiple of π tan β = 0
Hence,
[tex]\beta=n\pi[/tex]For
[tex]\tan \beta+1=0[/tex]This gives
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