Question

find 4 consecutive integers who's sum is 74

Answer 1

We have to find 4 consecutive integers which sum is 74.

We can start by calling x the smaller of the integers of the group.

Then, the others integers will be: (x+1), (x+2) and (x+3).

The sum of the four integers has to equal 74, so we can write:

$\begin{gathered} x+(x+1)+(x+2)+(x+3)=74 \\ 4x+(1+2+3)=74 \\ 4x+6=74 \\ 4x=74-6 \\ 4x=68 \\ x=\frac{68}{4} \\ x=17 \end{gathered}$

We now know that the smaller integer is 17, so the group is: 17, 18, 19 and 20.

Answer: 17, 18, 19 and 20.