Respuesta :

The form of the slope-intercept of the linear equation is

[tex]y=mx+b[/tex]

m is the slope

b is the y-intercept

Since the slope of the line is 2/3, then

[tex]m=\frac{2}{3}[/tex]

Substitute it in the form of the equation

[tex]y=\frac{2}{3}x+b[/tex]

Since the line passes through the point (-9, 5), then

Substitute x in the equation by -9 and y by 5 to find the value of b

[tex]\begin{gathered} 5=\frac{2}{3}(-9)+b \\ 5=-\frac{18}{3}+b \\ 5=-6+b \end{gathered}[/tex]

Add 6 to both sides

[tex]\begin{gathered} 5+6=-6+6+b \\ 11=b \end{gathered}[/tex]

Then the equation of the line is

[tex]y=\frac{2}{3}x+11[/tex]

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