The form of the slope-intercept of the linear equation is
[tex]y=mx+b[/tex]m is the slope
b is the y-intercept
Since the slope of the line is 2/3, then
[tex]m=\frac{2}{3}[/tex]Substitute it in the form of the equation
[tex]y=\frac{2}{3}x+b[/tex]Since the line passes through the point (-9, 5), then
Substitute x in the equation by -9 and y by 5 to find the value of b
[tex]\begin{gathered} 5=\frac{2}{3}(-9)+b \\ 5=-\frac{18}{3}+b \\ 5=-6+b \end{gathered}[/tex]Add 6 to both sides
[tex]\begin{gathered} 5+6=-6+6+b \\ 11=b \end{gathered}[/tex]Then the equation of the line is
[tex]y=\frac{2}{3}x+11[/tex]