We would like to find an equivalent expression for
[tex]7x^2\sqrt[]{2x^4}\cdot6\sqrt[]{2x^{12}}[/tex]To do this, first we have to remember the following rule
[tex]\sqrt[]{a}\sqrt[]{b}=\sqrt[]{ab}[/tex]Then
[tex]\begin{gathered} 7x^2\sqrt[]{2x^4}\cdot6\sqrt[]{2x^{12}}=(7x^2)(6)(\sqrt[]{2x^4})(\sqrt[]{2x^{12})} \\ =42x^2\sqrt[]{(2x^4)(2x^{12})} \\ =42x^2\sqrt[]{4x^{16}} \end{gathered}[/tex]To simplify the squared root we have to remember yet another rule
[tex](a^m)^n=a^{mn}[/tex]Hence
[tex]\begin{gathered} 7x^2\sqrt[]{2x^4}\cdot6\sqrt[]{2x^2}=42x^2\sqrt[]{(2x^8)^2} \\ =42x^2\cdot2x^8 \\ =84x^{10} \end{gathered}[/tex]Therefore the answer is C.