The density of water is,
[tex]d_w=1000kgm^{-3}[/tex]The density of mercury is,
[tex]d_m=13600kgm^{-3}[/tex]The relative density of mercury is the density of mercury concerning the density of water.
Thus, the relative density of mercury is,
[tex]\begin{gathered} \frac{d_m}{d_w}=\frac{13600}{1000}_{} \\ \frac{d_m}{d_w}=13.6 \end{gathered}[/tex]Hence, option A is the correct answer.