Question

is B the right answer? If not, which one is?

Answer 1

Given the rational function;

$f(x)=\frac{3x+4}{x(x-2)}$

To determine the constraint for this function, we shall set the denominator equal to zero;

$\begin{gathered} x(x-2)=0 \\ \text{Hence;} \\ x=0 \\ x-2=0 \\ x=2 \end{gathered}$

This means the equation does not exist when x = 0, and when x = 2.

ANSWER:

The correct answer is option C.