ANSWER:
STEP-BY-STEP EXPLANATION:
[tex]9x+4x^2=7+8y[/tex]Solving for x
[tex]\begin{gathered} 9x+4x^2-7-8y=7+8y-7-8y \\ 4x^2+9x-7-8y=0 \\ \text{ By means of the general equation} \\ x=\frac{-9\pm\sqrt[]{9^2-4\cdot4\cdot(-7-8y)}}{4\cdot2} \\ x=\frac{-9\pm\sqrt[]{128y+193}}{8} \end{gathered}[/tex]solve for y:
[tex]\begin{gathered} 9x+4x^2-7=7+8y-7 \\ 8y=4x^2+9x-7 \\ y=\frac{4x^2+9x-7}{8} \end{gathered}[/tex]