SOLUTION:
Case: Bearing and distances (Trigonometry)
Given: Position of ships A and B from the habour. The bearing of the ship B from the habour.
Ship A is 10 miles East of the habor
Ship B is south of Ship A
Ship B is at a bearing 36 degrees from the habor
Required:
To find the distance between the two ships in miles
Method:
First we sketch the problem and then apply trig ratio to solve
Considering triangle ABH and using trigonometry ratios
[tex]\begin{gathered} \tan \theta\text{ = }\frac{opp}{Adj} \\ \tan 53\text{ = }\frac{x}{10} \\ x=\text{ 1.327 }\times10 \\ x=\text{ 13.27} \end{gathered}[/tex]
Final answer:
The two ships are 13 miles apart
