SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
[tex]\begin{gathered} Let\text{ us represent apples with a,} \\ Then,\text{ pears with p,} \\ Then,\text{ oranges with o ,} \end{gathered}[/tex][tex]\begin{gathered} Then,\text{ we have that:} \\ 3a\text{ = 4 p -- equation 1} \\ 3p\text{ = 2 o -- equation 2} \\ Then,\text{ we need to compare:} \\ 3p\text{ = 2 o --equation 2} \\ and\text{ } \\ ?\text{ = 72 o -- equation 3} \end{gathered}[/tex][tex]\begin{gathered} cross-multiply,\text{ we have that:} \\ ?\text{ = }\frac{3\text{ x 72}}{2}=\text{ 3 x 36 = 108 p } \end{gathered}[/tex][tex]\begin{gathered} Recall\text{ that:} \\ 3a\text{ = 4p -- equation 1 } \\ x\text{ = 108 p --equation 4} \\ cross-multiply,\text{ we have that:} \\ x\text{ = }\frac{3\text{ x 108}}{4}=\text{ 3 x 27 = 81 apples} \end{gathered}[/tex]
CONCLUSION:
The final answer is:
[tex]81\text{ apples}[/tex]
