Question

slove by substitution. Show work.9.) 2y=4x+6 y=2x+3

Answer 1

Let:

$\begin{gathered} 2y=4x+6_{\text{ }}(1) \\ y=2x+3_{\text{ }}(2) \\ \end{gathered}$

Replace (2) into (1):

$\begin{gathered} 2(2x+3)=4x+6 \\ 4x+6=4x+6 \\ 0=0 \end{gathered}$

Therefore:

the system has infinitely many solutions