Respuesta :

Given:

[tex]\begin{gathered} Container-A \\ Diameter(A)=32feet,Height(A)=16feet \\ Container-B \\ Diamter(B)=30feet,Height(B)=18feet \end{gathered}[/tex]

To Determine: The volume of water remaining in container A

Solution

Let us determine the volume of both container A and container B

The containers are in the shape of a cylinder. The volume of a cylinder is given as

[tex]Volume(Cylinder)=\pi r^2h[/tex]

Substitute the given into the formula

[tex]\begin{gathered} radius(rA)=\frac{diamter(A)}{2}=\frac{32ft}{2}=16ft \\ radius(rB)=\frac{diameter(B)}{2}=\frac{30ft}{2}=15ft \end{gathered}[/tex][tex]\begin{gathered} V(A)=\pi(rA)^2hA \\ V(B)=\pi(rB)^2hB \\ V(A)=\pi(16)^2\times16=4096\pi ft^3 \\ V(B)=\pi(15)^2\times18=4050\pi ft^3 \end{gathered}[/tex]

The remaining volume of the water remaining in container A would be

[tex]\begin{gathered} Remaining=V(A)-V(B) \\ Remaining=4096\pi ft^3-4050\pi ft^3 \\ =46\pi ft^3 \\ =144.51ft^3 \\ \approx144.5ft^3 \end{gathered}[/tex]

Hence, the remaining volume of water in the container A is approximately 144.5 cubic foot

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