Question

normal population has a mean of 31 and standard deviation of 10. what proportion of the population is less than 30

Answer 1

Answer:

Given that,

The normal population has a mean of 31

standard deviation of 10

To find: The proportion of the population is less than 30

Explanation:

we can find the z score value by using the formula,

$z=\frac{x-m}{s}$

where m is the mean and s is the standard deviation.

Substitute the vaues we get,

$z=\frac{30-31}{10}$$z=-0.1$

To find the proportion of the population is less than 30.

we get,

$P(ZUsing standard normal table, we get[tex]P(Z<-0.1)=0.46017$

We get,

The proportion of the population is less than 30 is 0.46017.

Answer is:

The proportion of the population is less than 30 is 0.46017.