Question

Consider the function:h(x) = – 3x3 + 3x2 + 2x + 3Step 2 of 2: Find the value of h(3).

Answer 1

We have

$h(x)=-3x^3+3x^2+2x+3$

In order to find h(3) we need to substitute x with 3

$h(3)=-3(3)^3+3(3)^2+2(3)+3$$h(3)=-45$