ANSWER:
19/32
STEP-BY-STEP EXPLANATION:
We have the following sequence:
[tex]\frac{7}{32},\:\frac{10}{32},\:\frac{13}{32},\:\frac{16}{32},\:...[/tex]
We calculate the common difference:
[tex]\begin{gathered} d=\frac{16}{32}-\frac{13}{32}=\frac{3}{32} \\ \\ d=\frac{13}{32}-\frac{10}{32}=\frac{3}{32} \\ \\ d=\frac{10}{32}-\frac{7}{32}=\frac{3}{32} \\ \\ \text{ Therefore, the following term would be:} \\ \\ t=\frac{16}{32}+\frac{3}{32}=\frac{19}{32} \end{gathered}[/tex]
The correct answer is 19/32
