we have an exponential growth function
[tex]\begin{gathered} y=a(1+r)^x \\ y\leq90 \\ a(1+r)^x\leq90 \end{gathered}[/tex]where
a=28
r=85%=85/100=0.85
substitute
[tex]\begin{gathered} 28(1+0.85)^x\leq90 \\ 28(1.85)^x\leqslant90 \end{gathered}[/tex]For x=5 months
Find out the value of y and compare it with 90
[tex]\begin{gathered} y=28(1.85)^5 \\ y=607 \end{gathered}[/tex]607 > 90
Find out the value of x For y=90
[tex]\begin{gathered} 90=28(1.85)^x \\ \frac{90}{28}=(1.85)^x \end{gathered}[/tex]Apply log on both sides
[tex]log(\frac{90}{28})=x*log(1.85)^[/tex]x=1.9 months
therefore
Approximately every 2 months the plants will have to be moved to another site, leaving the initial quantity of 28 plants.
After 5 months the number of plants is about 607