Question

Triangle JKL was 90 clockwise about the origin. Triangle J’K’L is graphed below . What were the coordinates of the pre-image point L?

Answer 1

Answer:

The coordinates of the Preimage point L is;

$L=(2,4)$

Explanation:

Given the image J'K'L';

with coordinates;

$\begin{gathered} J^{\prime}=(-2,-1) \\ K^{\prime}=(1,4) \\ L^{\prime}=(4,-2) \end{gathered}$

A 90 degree clockwise rotation can be represented by the rule;

$(x,y)\rightarrow(y,-x)$

Where;

(x,y) is the preimage

(y,-x) is the image.

So, the coordinates of the preimage point L can be solved as;

$\begin{gathered} L(x,y)\rightarrow L^{\prime}(4,-2) \\ x=-(-2) \\ x=2 \\ y=4 \\ So; \\ L=(2,4) \end{gathered}$

Therefore, the coordinates of the Preimage point L is;

$L=(2,4)$