Given:
the length of the pendulum is
[tex]l=1\text{ m}[/tex]Required: the period of the pendulum.
Explanation:
the period of the pendulum of length l is given by
[tex]T=2\pi\sqrt[2]{\frac{l}{g}}[/tex]Plugging all the values in the above relation, we get
[tex]\begin{gathered} T=2\pi\sqrt[\placeholder{⬚}]{\frac{1\text{ m}}{9.8\text{ m/s}^2}} \\ T=2\times3.14\times0.32 \\ T=2.0\text{ s} \end{gathered}[/tex]Thus, the period of the pendulum is
[tex]2\text{ s}[/tex]