Question

you order twelve burritos to go from a Mexican restaurant 5 with hot peppers and 7 without however the restaurant forgot to label them if you pick 3 burritos at random find the probability that exactly to have hot peppers

Answer 1

The burritos with hot peppers is n(H) = 5.

The burritos without hot peppers is n(H') = 7.

Determine the propability for selected 3 burritos exactly 2 have hot peppers.

$\begin{gathered} P(H)=\frac{^5C_2\cdot^7C_1}{^{12}C_3} \\ =\frac{10\cdot7}{220} \\ =\frac{7}{22} \end{gathered}$

So, probability for selected 3 burritos, exactly two have hot peppers is 7/22.