Question

How many grams of silver are produced in the decomposition of 35.0 g silver oxide?

Answer 1

Answer:

32.6 g Ag.

Explanation:

What is given?

Mass of silver oxide (Ag2O) = 35.0 g,

Molar mass of Ag2O = 232 g/mol,

Molar mass of silver (Ag) = 108 g/mol.

Step-by-step solution:

First, let's convert 35.0 g of Ag2O to moles using its molar mass:

$35.0\text{ g Ag}_2O\cdot\frac{1\text{ mol Ag}_2O}{232\text{ g Ag}_2O}=0.151\text{ moles Ag}_2O.$

In the chemical equation you can see that 2 moles of Ag2O reacted produces 4 moles of Ag:

$0.151\text{ moles Ag}_2O\cdot\frac{4\text{ moles Ag}}{2\text{ moles Ag}_2O}=0.302\text{ moles Ag.}$

The final step is to convert 0.302 moles of Ag to grams using the molar mass of Ag, as follows:

$0.302\text{ moles Ag}\cdot\frac{108\text{ g Ag}}{1\text{ mol Ag}}=32.6\text{ g Ag.}$

The answer would be 32.6 g Ag.