Question

Write the equation of a line in the form y=Mx+b that passes through the point (3,6) and has a slope of -2/3. Sketch this line

Answer 1

$\begin{gathered} m=\frac{-2}{3} \\ P(3,6) \\ y=mx+b \\ U\sin g\text{ the given data} \\ y=\frac{-2}{3}x+b \\ 6=\frac{-2}{3}(3)+b \\ 6=-2+b \\ b=6+2 \\ b=8 \\ Hence \\ \text{The equation of the line is }y=\frac{-2}{3}x+8 \end{gathered}$