suppose that your boss must choose three employees in your office to attend a conference in jamaica. because all 18 of you want to go, he decides that the only fair way is to draw names out of a hat. what is the probability that you, sharon, and robert are chosen? enter a fraction or round your answer to 4 decimal places, if necessary.

Respuesta :

The probability that I, Sharon, and Robert are chosen is 0.0012

What is the formula for calculating combinations?

The equation  [tex]^{n}C_{r}=\frac{n!}{(n-r)! r!}[/tex] will be used to calculate combinations, where n is the overall number of things and r is the number of items that are being chosen at a time.

The total number of employees=18

The Boss must choose 3 employees to attend the conference.

The number of possible ways to choose 3 employees from the total of 18 employees is [tex]^{18}C_{3}[/tex] .

The equation  [tex]^{n}C_{r}=\frac{n!}{(n-r)! r!}[/tex] will be used to calculate combinations,.

So, [tex]^{18}C_{3}=\frac{18!}{(18-3)! 3!}[/tex]

    [tex]^{18}C_{3}=\frac{18!}{(15)! 3!}[/tex]  

    [tex]^{18}C_{3}=\frac{18 \times 17 \times 16 \times 15}{3 \times 2}[/tex]

     [tex]^{18}C_{3} =816[/tex]

The probability that I, Sharon, and Robert are chosen is  [tex]\frac{1}{816}[/tex] = 0.0012

To learn more about the combinations from the given link

https://brainly.com/question/11732255

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The probability that I, Sharon, and Robert are chosen is 0.0012

What is the formula for calculating combinations?

The equation   [tex]^{n}C_{r}=\frac{n!}{(n-r)! r!}[/tex]    will be used to calculate combinations, where n is the overall number of things and r is the number of items that are being chosen at a time.

The total number of employees=18

The Boss must choose 3 employees to attend the conference.

The number of possible ways to choose 3 employees from the total of 18 employees is [tex]^{18}C_{3}[/tex]   .

The equation  [tex]^{n}C_{r}=\frac{n!}{(n-r)! r!}[/tex]    will be used to calculate combinations,.

So,

[tex]^{18}C_{3}=\frac{18!}{(18-3)! 3!}^{18}C_{3}=\frac{18!}{(15)! 3!}^{18}C_{3}=\frac{18 \times 17 \times 16 \times 15}{3 \times 2}[/tex]

[tex]^{18}C_{3}=816[/tex]

The probability that I, Sharon, and Robert are chosen is  = 0.0012

To learn more about the combinations from the given link

brainly.com/question/11732255

#SPJ4

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