Question

Consider drawing with removing of 2 balls. What is the probability that

Answer 1

step 1

Find out the total possible outcomes

Find out the combination 2C8

$2C8=\frac{8!}{2!(8-2)!}=28$

step 2

Find out the combination 2C5 (red balls)

$2C5=\frac{5!}{2!(5-2)!}=10$

therefore

The probability is

P=10/28

simplify

P=5/14