Question

The solutions to (x + 4)2 - 2 = 7 areA) -1 and -7B) 1 and 7

Answer 1

We have the following equation:

$(x+4)^2\text{ - 2 = 7}$

Let's solve it, this way:

(x + 4) (x + 4) -2 = 7

x^2 + 4x + 4x + 16 - 2 = 7

x^2 + 8x + 14 = 7

x^2 + 8x + 14 - 7 = 0

x^2 + 8x + 7 = 0

(x - 7) (x - 1) = 0

x1 - 7 = 0

x2 - 1 = 0

$x_{1\text{ }}=7,x_2\text{ = 1}$

Now you can select the correct answer.