Let x and y represent the cost of one box of popcorn and one soft drink respectively.
Given;
Ms. Torres purchased two boxes of popcorn and three soft drinks for $6.05.
[tex]2x+3y=6.05\text{ -----1}[/tex]Also, Mr. Russo purchased three boxes of popcorn and five soft drinks for $9.50.
[tex]3x+5y=9.50\text{ ------2}[/tex]From the question we have generated a system of simultaneos equation.
we now need to solve the simultaneous equation to get the value of x and y.
Let's solve by elimination.
Firstly multiply equation 1 through by 3 and equation 2 by 2.
This is to have equal coefficient of x for the two equations, to make elimination possible.
[tex]\begin{gathered} 2x+3y=6.05\text{ -----1 }\times3 \\ 6x+9y=18.15\text{ ------3} \\ \\ 3x+5y=9.50\text{ ------2 }\times2 \\ 6x+10y=19.00---------4\text{ } \end{gathered}[/tex]Now we have equation 3 and 4.
Let us subtract equation 3 from 4.
[tex]\begin{gathered} 6x+10y-6x-9y=19.00-18.15 \\ 6x-6x+10y-9y=0.85 \\ y=0.85 \end{gathered}[/tex]We can now substitute the value of y into equation1 to get x