Respuesta :

ANSWER:

When evaluating x in the function we have that the function is not defined

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]f(x)=\frac{3x^2-8x-3}{x^2-9}_{}[/tex]

replacing x = -3, therefore:

[tex]\begin{gathered} f(-3)=\frac{3\cdot(-3^2)-8\cdot-3-3}{(-3)^2-9} \\ f(-3)=\frac{3\cdot9+24-3}{9-9}=\frac{48}{0}=\text{ not defined} \end{gathered}[/tex]

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