y = mx + b
slope = -5/3
the slope of the parallel line is -5/3
[tex]\begin{gathered} 4=-\frac{5}{3}(-5)+b \\ 4=\frac{25}{3}+b \\ 4-\frac{25}{3}=\frac{25}{3}+b-\frac{25}{3} \\ -\frac{13}{3}=b \end{gathered}[/tex]the equation of the parallel line is
[tex]y=-\frac{5}{3}x-\frac{13}{3}[/tex]b. the slope of the perpendicular line is 3/5
[tex]\begin{gathered} 4=\frac{3}{5}(-5)+b \\ 4=-3+b \\ 4+3=-3+b+3 \\ 7=b \end{gathered}[/tex]the equation perpendiculat to this line is
[tex]y=\frac{3}{5}x+7[/tex]