Question

The equation for the line that has a slope of and passes through (0, 10) is co - 3x + 10 3 g2 y = 10x 13 3 8 :: y = - 10

Answer 1

$\begin{gathered} \text{slope = m = -}\frac{3}{8} \\ u\sin g\text{ the slope form equation} \\ m=\frac{y-y_1}{x-x_1} \\ m=\frac{y-10}{x-0} \\ m=\frac{y-10}{x} \\ mx=y-10 \\ y=mx+10 \\ y=-\frac{3}{8}x+10 \end{gathered}$